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修复订阅列表为空时使用删除订阅命令无法跳出的问题

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This commit is contained in:
Azide
2022-05-11 18:27:47 +08:00
parent 84e497e65a
commit 227cf0cfc1
3 changed files with 103 additions and 25 deletions
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src/plugins/nonebot_bison/config_manager.py
+30 -25
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@@ -244,33 +244,38 @@ def do_del_sub(del_sub: Type[Matcher]):
config: Config = Config()
user_info = state["target_user_info"]
assert isinstance(user_info, User)
sub_list = config.list_subscribe(
# state.get("_user_id") or event.group_id, "group"
user_info.user,
user_info.user_type,
)
res = "订阅的帐号为：\n"
state["sub_table"] = {}
for index, sub in enumerate(sub_list, 1):
state["sub_table"][index] = {
"target_type": sub["target_type"],
"target": sub["target"],
}
res += "{} {} {} {}\n".format(
index, sub["target_type"], sub["target_name"], sub["target"]
try:
sub_list = config.list_subscribe(
# state.get("_user_id") or event.group_id, "group"
user_info.user,
user_info.user_type,
)
platform = platform_manager[sub["target_type"]]
if platform.categories:
res += " [{}]".format(
", ".join(
map(lambda x: platform.categories[Category(x)], sub["cats"])
)
assert sub_list
except AssertionError:
await del_sub.finish("暂无已订阅账号\n请使用“添加订阅”命令添加订阅")
else:
res = "订阅的帐号为：\n"
state["sub_table"] = {}
for index, sub in enumerate(sub_list, 1):
state["sub_table"][index] = {
"target_type": sub["target_type"],
"target": sub["target"],
}
res += "{} {} {} {}\n".format(
index, sub["target_type"], sub["target_name"], sub["target"]
)
if platform.enable_tag:
res += " {}".format(", ".join(sub["tags"]))
res += "\n"
res += "请输入要删除的订阅的序号\n输入'取消'中止"
await bot.send(event=event, message=Message(await parse_text(res)))
platform = platform_manager[sub["target_type"]]
if platform.categories:
res += " [{}]".format(
", ".join(
map(lambda x: platform.categories[Category(x)], sub["cats"])
)
)
if platform.enable_tag:
res += " {}".format(", ".join(sub["tags"]))
res += "\n"
res += "请输入要删除的订阅的序号\n输入'取消'中止"
await bot.send(event=event, message=Message(await parse_text(res)))
@del_sub.receive()
async def do_del(event: Event, state: T_State):